Detailed
Answers to Initial Practice:
Equations and Their Graphs
Now let's
work through the solution to this problem by going through the
steps outlined in this unit. The equation you should have graphed
is y = 2x + 2.
You should have created a table to obtain some points. A sample using 0, 1, 2, and 3 for x is shown in the table.
x y 0 2 1 4 2 6 3 8 To obtain y values, plug the x values into the equation y = 2x + 2 and compute.
x = 0
y = 2 (0) + 2
y = 0 + 2
y = 2x = 1
y = 2 (1) + 2
y = 2 + 2
y = 4x = 2
y = 2 (2) + 2
y = 4 + 2
y = 6x = 3
y = 2 (3) + 2
y = 6 + 2
y = 8
The points that we have defined here are:(0, 2), (1, 4), (2, 6), (3, 8)
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What if your graph does not look like this? If your graph does not look like the one shown here, read through the suggestions below to determine where you may have made a mistake.
If any of your points do not lie on your straight line:
IMPORTANT: You should always plot at least three points before drawing your line. This serves as an extra check because if one points does not lie on your line, you made a mistake somewhere.
If your graph looks like the one shown here you have switched your x and y values when plotting. Remember that points are given in the coordinate notation of (x, y), with x first and y second. Be sure that you plotted the points correctly. If you do not understand how plotting of points is done, reread the section on plotting points in the second unit and then go to the additional practice for this unit. |
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